Tentu kan nilay suku ke 12 dari barisan aritmatika
a,2,7,12,17,22.....
B,41,32,27,2013.....
C,3,7,11,15,19......
D,2,3½,5,6½,8.....
C,9,0-9,-18,-27......
a,2,7,12,17,22.....
B,41,32,27,2013.....
C,3,7,11,15,19......
D,2,3½,5,6½,8.....
C,9,0-9,-18,-27......
u(n) = a + ((n-1).b) → a = suku awal, b = beda, u(n) = suku ke-n
a. a = 2, b = +5
u12 = a + 11.b
= 2 + 11.5
= 2 + 55
= 57
b. a = 41, b = -7
u12 = a + 11.b
= 41 + 11.(-7)
= 41 + (-77)
= -36
c. a = 3, b = +4
u12 = a + 11.b
= 3 + 11.4
= 3 + 44
= 47
d. a = 2, b = +1½
u12 = a + 11.b
= 2 + 11.1½
= 2 + 16,5
= 18,5 atau 18 ½
e. a = 9, b = -9
u12 = a + 11.b
= 9 + 11.(-9)
= 9 + (-99)
= -90
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